util: remove unused fast path in internal debuglog

Trott · BethGriggs · commit 2b082def2e81 · 2022-01-24T17:36:04.000Z
The internal `debuglog()` is never called with 0 parameters. Remove the fast-path for that situation. If it ever occurs, it will fall through to the default path. PR-URL: #41605 Reviewed-By: Anna Henningsen <anna@addaleax.net> Reviewed-By: Michaël Zasso <targos@protonmail.com>
diff --git a/lib/internal/util/debuglog.js b/lib/internal/util/debuglog.js
@@ -81,7 +81,6 @@ function debuglog(set, cb){
 if (typeof cb === 'function')
 cb(debug);
 switch (args.length){
- case 0: return debug();
 case 1: return debug(args[0]);
 case 2: return debug(args[0], args[1]);
 default: return debug(...new SafeArrayIterator(args));
@@ -95,7 +94,6 @@ function debuglog(set, cb){
 };
 const logger = (...args) =>{
 switch (args.length){
- case 0: return debug();
 case 1: return debug(args[0]);
 case 2: return debug(args[0], args[1]);
 default: return debug(...new SafeArrayIterator(args));

-Original file line number
+Diff line change
 if(typeofcb==='function')
 cb(debug);
 switch(args.length){
 -case0: returndebug();
 case1: returndebug(args[0]);
 case2: returndebug(args[0],args[1]);
 default: returndebug(...newSafeArrayIterator(args));
 };
 constlogger=(...args)=>{
 switch(args.length){
 -case0: returndebug();
 case1: returndebug(args[0]);
 case2: returndebug(args[0],args[1]);
 default: returndebug(...newSafeArrayIterator(args));