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Confusing error handling for KeyboardInterrupt#341
Description
I reported this issue on the Python tracker but got no answer.
If you trigger KeyboardInterrupt in a coroutine and catch it, the program terminates cleanly:
import asyncio async def bar(): raise KeyboardInterrupt loop = asyncio.get_event_loop() try: loop.run_until_complete(bar()) except KeyboardInterrupt: print("It's ok") finally: loop.stop() loop.close() This outputs:
It's ok
However, if you wrap the coroutine in a Task, you will get a mixed behavior:
try: task = asyncio.ensure_future(bar()) loop.run_until_complete(task) except KeyboardInterrupt: print("It's ok") This outputs:
It's ok Task exception was never retrieved future: <Task finished coro=<bar() done, defined at ki_bug.py:4> exception=KeyboardInterrupt()> Traceback (most recent call last): File "ki_bug.py", line 10, in <module> loop.run_until_complete(main_future) File "/usr/lib/python3.5/asyncio/base_events.py", line 325, in run_until_complete self.run_forever() File "/usr/lib/python3.5/asyncio/base_events.py", line 295, in run_forever self._run_once() File "/usr/lib/python3.5/asyncio/base_events.py", line 1258, in _run_once handle._run() File "/usr/lib/python3.5/asyncio/events.py", line 125, in _run self._callback(*self._args) File "/usr/lib/python3.5/asyncio/tasks.py", line 239, in _step result = coro.send(None) File "ki_bug.py", line 5, in bar raise KeyboardInterrupt KeyboardInterrupt We have several contradictory behaviors: the KeyboardInterrupt is raised, and captured by the future (since your can do task.exception() to suppress the stracktrace) but also catched by except while the program is allowed to continue, yet still the stack trace is displayed and eventually the program return code will be 0.
It's very confusing.
I believe it's because exceptions don't break out the event loop, but KeyboardInterrupt is having some kind special treatment.